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Fenton氧化破解剩余污泥中的胞外聚合物
摘要点击 2438  全文点击 1661  投稿时间:2008-02-29  修订日期:2008-03-22
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中文关键词  Fenton试剂  胞外聚合物  剩余污泥  多聚糖  蛋白质  SCOD  污泥粒径分布
英文关键词  Fenton reagent  extracellular polymeric substances (EPS)  excess sludge  polysaccharide  protein  soluble chemical oxygen demand (SCOD)  sludge particulate distribution
作者单位
李娟 湖南大学环境科学与工程学院长沙 410082 
张盼月  
曾光明  
宋相国  
董金华  
张海燕  
吴珍  
贾晓蕾  
中文摘要
      利用Fenton试剂的强氧化性破解剩余污泥中的胞外聚合物(EPS),通过释放出的多聚糖、蛋白质浓度以及SCOD的变化表征EPS的破解程度,旨在找出Fenton氧化破解EPS的适宜反应条件.结果表明,pH = 2.5,反应时间90 min,H2O2/Fe2+(质量比)= 8∶1,温度65~70℃为适宜反应条件.该条件下经Fenton氧化,污泥上清液中的SCOD、多聚糖和蛋白质浓度分别由45.88、 10.96和11.99 mg·L-1增加到684.93、 382.17和302.62 mg·L-1;污泥颗粒平均粒径和中值粒径分别由供试污泥的838.89 μm和859.20 μm减小到137.22 μm和148.69 μm.Fenton氧化可以有效破解污泥中的EPS,提高污泥的无机化程度,有利于污泥的减量化和资源化.
英文摘要
      Fenton oxidation was used to disintegrate extracellular polymeric substances (EPS) of excess sludge with its strong oxidation ability. The concentration of polysaccharide, protein and the change of soluble chemical oxygen demand (SCOD) disintegrated from EPS represent the EPS disintegration degree. The objective of this study is to optimize the operational conditions for EPS disintegration with Fenton oxidation. It is shown that the optimal operational condition is as following: pH=2.5, reaction time = 90min, H2O2/Fe2+ (weight dosage ratio) = 8∶1 and reaction temperature is about 65-70℃. Under this condition after the Fenton oxidation, SCOD, concentration of polysaccharide, protein in the supernate increase from 45.88, 10.96 and 11.99 mg·L-1 to 684.93, 382.17 and 302.62 mg·L-1, respectively; the average diameter and the median diameter of sludge particulates reduce from 838.89 μm and 859.20 μm to 137.22 μm and 148.69 μm, respectively. As a result, EPS is effectively disintegrated by Fenton oxidation and the sludge is greatly mineralized, which benefits the further sludge reduction and utilization.

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