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垂直潜流人工湿地中有机物去除动态规律研究
摘要点击 1589  全文点击 1951    修订日期:2007-10-24
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中文关键词  人工湿地  有机物  动态规律  去除  垂直潜流
英文关键词  constructed wetland  organic matter  dynamic rule  removal  vertical-flow
作者单位
叶建锋 上海市环境科学研究院上海 200233 
徐祖信 同济大学环境科学与工程学院上海 200092 
李怀正 上海市环境科学研究院上海 200233 
中文摘要
      在分析垂直潜流人工湿地不同高度有机物去除率及其形态变化的基础上,推求出各形态有机物在垂向沿程的平均去除速率,建立了进水浓度和进水水力负荷规律曲线.结果表明,在本实验条件下,垂直潜流人工湿地中有机物的去除主要集中在布水管至布水管下10 cm的基质层内,进水水力负荷越小,该基质层内有机物的去除率也越高;在以粗砂作为垂直潜流人工湿地的基质、进水水力负荷≤0.5 m/(m·d)的条件下,垂直潜流人工湿地对有机物去除的有效高度为60 cm;布水管下10 cm基质层不同类型有机物的平均降解速率都处于最大,随着垂向沿程深度的增加,各类型有机物的平均降解速率都呈较大幅度递减趋势;以砂子为基质的垂直潜流人工湿地进水浓度和进水水力负荷规律曲线可表示为(cincout)×q=1107.02-2.96 cin×q.
英文摘要
      Based upon the analysis of the removal rate and form change of the organic pollutants with the different height of the vertical-flow constructed wetl and, it comes to the conclusion of the average longitudinal removal rate of variant forms organics and presents the influent concentration and the hydraulic load curve. The results indicated that: Under this experimental condition, the reduction of the organics in the vertical subsurface flow constructed wetland mainly occurred within the 0-10 cm substrate below the pipe distributor. In the meantime, the smaller the hydraulic load of influent, the higher the removal ratio of the organic pollutants in the substrate section. Under the condition that the vertical subsurface flow constructed wetland used the coarse sands as the substrate and kept the influent hydraulic load less than or equal to 0.5 m3(m·d), the effective height of the organics removal was 60 cm. It also showed that the average degradation rate of different kinds of the organic pollutants has a maximum value in the 0-10 cm substrate section below the pipeline. Moreover, the degradation ratio of different kinds of the organics is in significant decreasing tendency with increasing the depth of the longitudinal direction along the pipe. Using sands as the substrate in the vertical subsurface flow constructed wetland, the relationship of the influent concentration and influent hydraulic load can be expressed by formula:(cincout)×q=1107.02-2.96 cin×q.

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