| Ce3+与Cu2+协同强化芬顿体系氧化苯酚的效能与机制研究 |
| 摘要点击 3894 全文点击 1374 投稿时间：2015-12-24 修订日期：2016-03-21 |
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| 中文关键词 三金属芬顿体系 铈离子 苯酚 羟基自由基 协同强化 醌类物质 |
| 英文关键词 trimetal Fenton system cerium ion phenol hydroxyl radical synergistic enhancement quinone-like substrates |
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| 中文摘要 |
| 研究了Ce3+与Cu2+协同强化芬顿体系在不同初始条件下对水中苯酚的氧化效能与机制. 结果表明，在pH适用范围的宽度和H2O2浓度变化方面，Ce3+/Cu2+/Fe2+/H2O2体系比传统的芬顿体系更具有优势，该体系在pH=5.0、H2O2浓度为2.0 mmol·L-1的条件下，仍可以对苯酚保持相对较高的氧化效能；Cu2+可能会借助反应过程中的中间产物（醌类物质）生成Cu+，Cu+催化H2O2分解生成·OH，Ce3+可能促进体系内醌类物质的形成，加快Fe3+与Fe2+的循环效能，在一定程度上提高了芬顿体系中H2O2分解生成·OH的速率，说明Cu2+与Ce3+对芬顿体系的强化作用具有协同性；自由基终止剂依然可以抑制Ce3+、Cu2+强化的芬顿体系对苯酚的降解，由此说明体系中起到氧化作用的活性物种仍然是羟基自由基（·OH）. |
| 英文摘要 |
| Synergistic effect of Ce3+ and Cu2+ on the oxidation efficiency of phenol in different initial pH and H2O2 concentrations by Fenton processes was studied. The experiment results illustrated that Ce3+/Cu2+/Fe2+/H2O2 system had a wider scope of application than Fenton process in the aspect of pH and H2O2 concentration. Phenol was still efficiently degraded by Ce3+/Cu2+/Fe2+/H2O2 at a higher pH (pH=5.0) and a higher H2O2 concentration (2.0 mmol·L-1). In addition, Cu2+ could react with quinone-like substrates, the oxidation intermediates of phenol, to produce Cu+, which could catalyze the decomposition of H2O2 to form·OH, while Ce3+ could accelerate the formation of quinone-like substrates and facilitate the cycling of Fe3+ and Fe2+, to enhance the decomposition of H2O2 to form·OH, the mechanism analysis illuminated the synergy of Ce3+ and Cu2+. The reactive species in Ce3+/Cu2+/Fe2+/H2O2 system was still proved to be·OH, resulting from the scavenging experiments by adding different radical scavengers. |
